NHST and sampling distributions
University of Amsterdam
4 September 2026
In block 1 we aim to:
Reading: Chapters 1–8.8
In this lecture we aim to:
Reading: Chapters 1, 2, 3 (§1.1–1.8, §2.1–2.9, §3.1–3.8)
Two halves running side by side: reasoning (arguments, rationality, critical thinking) and statistics. These are the statistics lectures.
Each block closes with an interim exam.
Not just computing the right number. Three levels, and we want all three:
Source: ARTIST
Field, Discovering Statistics Using JASP.
Every section carries a letter for difficulty, each rhyming with what it does to your brain:
In this course we focus mostly on A and B.
Worth looking out for:
Suppose we want to find out whether someone is a physics expert.
\(H_0\)
\(H_A\)
\[P(k \text{ success out of } n \text{ trials} \mid \text{probability } p) = {n\choose k}p^k(1-p)^{n-k}\] where \[ {n\choose k} = \frac{n!}{k!(n-k)!} \]
With values:
The number of correct answers is a test statistic.
A statistic that summarizes the data and is used for hypothesis testing, because we know how it’s distributed under different hypotheses
Common test statistics:
The candidate had 8 items correct. Can we conclude they are a physics expert?
Conditional probability of the observed test statistic or more extreme assuming the null hypothesis is true.
Reject \(H_0\) when:
\[P(k \geq 8 \mid H_0) = 0.044 + 0.01 + 0.001 = 0.055\]
Alpha determines how willingly we reject the null hypothesis:
No scientific worker has a fixed level of significance at which from year to year, and in all circumstances, he rejects hypotheses; he rather gives his mind to each particular case in the light of his evidence and his ideas. (Fisher, 1956)
The stricter the \(\alpha\), the further into the tail the region starts. Our candidate’s 8 would only count as “significant” at \(\alpha = .10\).
Fisher asked how surprising is this data? Neyman and Pearson asked a different question: which mistakes am I willing to make, and how often?
But we have no clue what this distribution could look like.
For now let’s assume the probability of answering an item correctly is .75
\(\alpha\) — Type I error
\(\beta\) — Type II error
Power — correctly reject \(H_0\)
\(1-\alpha\) — correctly accept \(H_0\)
Play around with this app to get an idea of the probabilities

Scientific & Statistical Reasoning